Coulombic efficiency calculator: CE per cycle, average CE and capacity retention
Coulombic efficiency (CE) is the capacity a cell gives back divided by the capacity put in during the same cycle. For a cathode half-cell or a full cell that is discharge / charge; for a lithium-metal or anode half-cell (Li||Cu) it is stripping / plating, the charge capacity over the discharge capacity. If every cycle keeps the same CE and nothing replaces the lost lithium, the capacity left after n cycles is CEⁿ: 99.7 % CE falls to 80 % after about 74 cycles, 99.9 % after about 223. Paste your cycling data to get the CE of every cycle, the average over the cycles you choose, the first-cycle loss and the retention.
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At a glance
| Formula | CE = Q_out / Q_in: discharge / charge (cathode, full cell); charge / discharge (anode or Li-metal half-cell) |
|---|---|
| Average | Mean of per-cycle CE over your range, and Σ Q_out / Σ Q_in |
| Retention | Q_out,n / Q_out,ref; projection R = ICE × CEⁿ, CE needed = (R / ICE)^(1/n) |
| Input | Cycle, charge, discharge (mAh, mAh/g, Ah, µAh, mAh/cm²), or one pair of values |
| Output | CE per cycle, first-cycle CE and loss, retention, projection; plots (PNG, SVG) and CSV |
| Limits | CEⁿ assumes constant CE and no lithium reservoir; half-cells usually fade more slowly |
| Runs in | Your web browser; nothing is uploaded |
| Price | Free, no account needed |
What it does
How to use the coulombic efficiency calculator
- Pick the cell typeCathode half-cell or full cell: CE = discharge / charge. Anode or Li-metal half-cell (Li||Cu, graphite, silicon or hard carbon vs Li or Na): CE = charge / discharge, the stripping or delithiation over the plating or lithiation.
- Paste the cycling dataThree columns from the cycler export: cycle number, charge capacity, discharge capacity (a header row is skipped). Swap the column order if your file lists discharge first. Or switch to One cycle and type two values.
- Choose the rangePick the cycles to average (leave out the formation cycles), the reference cycle for retention, how many cycles to project and the target retention.
- Read and exportRead the average CE, first-cycle CE and loss, retention and projection; check the CE plot for outliers; download the plots and the CSV.
How it works
CE = Qout / Qin Rn = ICE × CEⁿ CEneeded = (R / ICE)1/n
Which capacity is “out”. CE is the charge recovered over the charge put in during one cycle. In a lithium||copper cell lithium is plated on copper and then stripped, and the average CE is the total stripping capacity over the deposited capacity (Nat Commun 2025, doi:10.1038/s41467-025-59955-0). For an anode half-cell the same holds with desodiation or delithiation over sodiation or lithiation: a hard carbon electrode with a first charge of 298 mAh g⁻¹ and discharge of 370 mAh g⁻¹ has an initial CE of 80.5 % (Chem Sci 2026, doi:10.1039/d6sc04167a). In a full cell (cathode against anode) it is discharge over charge: 99.94 / 117.35 mAh g⁻¹ = 85.16 % (iScience 2025, doi:10.1016/j.isci.2025.114581). The calculator applies discharge / charge to cathode half-cells and full cells and charge / discharge to anode and Li-metal half-cells, and reports the capacity lost in each cycle as Qin − Qout.
First cycle. The initial Coulombic efficiency (ICE) is low because active lithium or sodium is consumed in forming the interphase and trapped in the electrode; it sets the inventory left for every later cycle (Adv Sci 2026, doi:10.1002/advs.77874; Chem Sci 2026). Not all of a cathode’s first-cycle loss is permanent: in NCM/Li half-cells most of it was kinetic and recoverable with a constant-potential step at the end of discharge, and less than 10 mAh g⁻¹ was irreversible (PCCP 2016, doi:10.1039/c5cp07718d).
Average CE. The tool reports the arithmetic mean of the per-cycle CE over the range you choose, the way cycle-by-cycle Li||Cu data are summarised (Angew Chem 2026, doi:10.1002/anie.9595705), and the charge-weighted value Σ Qout / Σ Qin (Nat Commun 2025). Capacity retention is the out-capacity of a cycle divided by that of the reference cycle.
From CE to cycle life. When there is no reservoir, every inefficiency removes inventory for good, so the retention after n cycles is R = ICE × CEⁿ and the average CE needed for a target is (R / ICE)1/n: for 80 % after 200 cycles, at least 99.89 % with ICE = 100 % and 99.94 % with ICE = 90 %; a cell averaging 99.7 % reaches 80 % after about 74 cycles, one averaging 99.9 % after about 223 (Adv Sci 2026). The calculator gives CEⁿ, the cycles to the target, n = ln(R / ICE) / ln CE, and the CE needed. In a graphite cell, an average CE of 99.00 % loses up to 60 % of the capacity in 100 cycles, and adding 0.01 % to the CE roughly doubles the cycle life (Angew Chem 2026).
Limits. CEⁿ is an upper bound for an anode-free cell: it assumes a constant CE, no loss on the cathode side and no reactivation of dead metal (Adv Sci 2026). In the other direction, lithium metal electrodes act as reservoirs that make up for lost lithium and mask parasitic reactions (Angew Chem 2026), and a half-cell with a nearly unlimited lithium supply does not show the capacity loss a cell with limited lithium suffers (Small Sci 2025, doi:10.1002/smsc.202500131). So a half-cell’s capacity usually fades more slowly than CEⁿ; the tool prints the measured retention next to the CEⁿ prediction for the same cycles so you can see the gap. CE values also depend on the protocol (current, capacity, substrate), so compare them only under the same conditions.
Worked example: 30 cycles of a cathode half-cell (illustrative data)
The built-in example is an illustrative cathode half-cell, not a measurement: 30 cycles in mAh g⁻¹, charge 228.4 and discharge 201.6 in cycle 1, falling to 193.1 and 192.7 in cycle 30. Cell type: cathode, so CE = discharge / charge.
- First cycle. CE = 201.6 / 228.4 = 88.27 %; the first-cycle loss is 228.4 − 201.6 = 26.8 mAh g⁻¹, 11.7 % of the charge.
- Average CE. Cycles 2 and 3 are still settling (98.09 % and 99.25 %), so average cycles 4–30: the mean of the 27 per-cycle values is 99.791 % (Σ discharge / Σ charge gives the same to four figures).
- Retention. Against cycle 4 (199.4 mAh g⁻¹), cycle 30 keeps 192.7 / 199.4 = 96.64 %. CE26 = 0.9979126 predicts 94.70 %: the half-cell’s lithium counter electrode makes up part of the loss, so the capacity fades more slowly than CEⁿ.
- Projection. If 99.791 % held, 500 more cycles would leave 0.99791500 = 35.08 % (67.6 mAh g⁻¹ from 192.7), and 80 % would be reached after ln 0.8 / ln 0.99791 = 106.5 cycles. Keeping 80 % for 500 cycles needs an average CE of 0.81/500 = 99.955 %, or 99.980 % if the 88.27 % first cycle also counts.
One cycle. The hard carbon half-cell in Chem Sci 2026 gave 370 mAh g⁻¹ on sodiation (discharge) and 298 mAh g⁻¹ on desodiation (charge): in One cycle mode, capacity in 370 and out 298 give CE = 80.54 %, the 80.5 % reported, and a first-cycle loss of 72 mAh g⁻¹.
Frequently asked questions
How do you calculate Coulombic efficiency?
Divide the capacity taken out in a cycle by the capacity put in during that cycle. For a cathode half-cell or a full cell, CE = discharge capacity / charge capacity; for a Li||Cu or anode half-cell, CE = stripping (charge) capacity / plating (discharge) capacity. Multiply by 100 for percent.
What is initial Coulombic efficiency (ICE)?
The CE of the first cycle. It is usually much lower than later cycles because lithium or sodium is consumed in forming the solid electrolyte interphase and trapped in the electrode; a hard carbon half-cell with 370 mAh/g in and 298 mAh/g out has an ICE of 80.5 %. The difference, in − out, is the first-cycle (irreversible) capacity loss.
How is the average Coulombic efficiency calculated?
Either as the arithmetic mean of the CE of each cycle in a range, or as the total capacity out over the total capacity in (for a Li||Cu cell, total stripping over total plating). Leave out formation cycles so the first-cycle loss does not drag the average down; the calculator gives both values for the range you choose.
How does Coulombic efficiency relate to cycle life?
With a constant CE and no lithium reservoir, the capacity left after n cycles is CEⁿ (times the first-cycle CE if counted). 99.7 % reaches 80 % retention after about 74 cycles and 99.9 % after about 223; keeping 80 % for 500 cycles needs about 99.96 %.
Why does my cell keep more capacity than CEⁿ predicts?
A half-cell or a cell with excess lithium metal has a reservoir that replaces the lost lithium, which hides the parasitic losses. CEⁿ describes a cell with no reservoir, such as an anode-free cell, and even there it is an upper bound because it ignores cathode-side loss.
Why is my Coulombic efficiency above 100 %?
Usually the wrong step is taken as “out”: in a Li||Cu or anode half-cell the discharge is the plating, so CE = charge / discharge.
Does the capacity unit matter?
No. CE and retention are ratios, so mAh, Ah, mAh/g or mAh/cm² all give the same result as long as both columns use the same unit; the unit only labels the losses and the projected capacity.
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